hacker earth java if else problem

Using "if-else" you can perform decision making in Java. See the flowchart below (taken from wikipedia):

This problem will test your knowledge on "if-else" statements.

Given an integer N as input, check the following:

• If N is odd, print "Weird".
• If N is even and, in between the range of 2 and 5(inclusive), print "Not Weird".
• If N is even and, in between the range of 6 and 20(inclusive), print "Weird".
• If N is even and N>20, print "Not Weird".

We given you partially completed code in the editor, complete it to solve the problem.

Input Format

There is a single line of input: integer N.

Constraints 
1≤N≤100

Output Format

Print "Weird" if the number is weird. Otherwise, print "Not Weird". Do not print the quotation marks.

Sample Input 1

3

Sample Output 1

Weird

Sample Input 2

24

Sample Output 2

Not Weird

solution

-------------------------------------------------------------------------------

 import java.io.*;
    import java.util.*;
    import java.text.*;
    import java.math.*;
    import java.util.regex.*;

    public class Solution {

        public static void main(String[] args) {

            Scanner sc=new Scanner(System.in);
            int n=sc.nextInt();            
            String ans="";
            if(n%2==1){
              ans = "Weird";
            }
            else{
            
               //Complete the code
                
            }
            System.out.println(ans);
            
        }
    }